A small block slides with velocity 0.5
on the horizontal frictionless surface as shown in the figure. The block leaves the surface at point C. The angle
in the figure is-

Text Solution
Verified by ExpertsThe correct answer is:
B

mg cos θ – N=
; N = mg cos θ – 
N = 0 ⇒ mg cos θ = 
v =
or cos θ =
.….(i)
From energy conservation
m
= mgR(1 – cos θ )
⇒
–
= gR – gR cos θ …(ii)
From (i) and (ii) θ = cos –1 
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